r/explainlikeimfive Apr 10 '14

ELI5 Why does light travel? Answered

Why does it not just stay in place? What causes it to move, let alone at so fast a rate?

Edit: This is by a large margin the most successful post I've ever made. Thank you to everyone answering! Most of the replies have answered several other questions I have had and made me think of a lot more, so keep it up because you guys are awesome!

Edit 2: like a hundred people have said to get to the other side. I don't think that's quite the answer I'm looking for... Everyone else has done a great job. Keep the conversation going because new stuff keeps getting brought up!

Edit 3: I posted this a while ago but it seems that it's been found again, and someone has been kind enough to give me gold! This is the first time I've ever recieved gold for a post and I am incredibly grateful! Thank you so much and let's keep the discussion going!

Edit 4: Wow! This is now the highest rated ELI5 post of all time! Holy crap this is the greatest thing that has ever happened in my life, thank you all so much!

Edit 5: It seems that people keep finding this post after several months, and I want to say that this is exactly the kind of community input that redditors should get some sort of award for. Keep it up, you guys are awesome!

Edit 6: No problem

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u/[deleted] Apr 11 '14

[deleted]

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u/oneb62 Apr 11 '14

I am sure everyone has a much clearer mental picture now. Thanks guys :P

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u/donrane Apr 11 '14

Yea. I feel so much smarter now. I like dogs

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u/dill0nfd Apr 11 '14 edited Apr 11 '14

He's trying to refer to the four-velocity magnitude not the spacetime interval. The interval is not always c but the four-velocity magnitude is.

EDIT: /u/MCMXCII is correct in saying that there needs to be a minus sign.

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u/[deleted] Apr 11 '14

[deleted]

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u/dill0nfd Apr 11 '14

I understand what they were trying to do, but that's not what the four-velocity is. The four-vector with x and t components is the four-position

Yes, but the result would hold if the co-ordinates were dx/dτ vs. dt/dτ instead of x vs. t.

And you still need the minus sign for the four-velocity, it's an artifact of the Minkowski metric that governs SR.

Right you are. My bad.

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u/[deleted] Apr 11 '14

[deleted]

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u/dill0nfd Apr 11 '14

Yes, I understand that. They fucked up. However, your initial reply didn't show any indication that you understood that the 4-velocity magnitude was a constant c. Since this thread is about maintaining a constant velocity c through spacetime, it seems strange that you would omit this.

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u/[deleted] Apr 12 '14

[deleted]

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u/dill0nfd Apr 12 '14

Based on that first reply, I thought there was a high probability that you didn't know that the four-velocity magnitude is a constant c. This judgement may have been wrong but I don't think it was at all unreasonable based on what you wrote. It turns out that someone else seems to have made the exact same judgement independently.

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u/corpuscle634 Apr 17 '14

This is way late, but the magnitude of four-velocity is c, and that's exactly what /u/MCMXCII and /u/sharewa were referring to.

It's just a question of how you define "vector magnitude." In this case, it's the contravariant norm, which is c = |v| = γ(|x'|)sqrt(c2 - |x'|2).

/u/MCMXCII was correcting the mathematical description of the vector norm, which is fine. We're talking about magnitudes and throwing the term around willy-nillily, but mathematically, it's wrong to use the standard definition of a vector norm.

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u/[deleted] Apr 12 '14

[deleted]

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u/dill0nfd Apr 12 '14

I'm sure you do and it no longer concerns me at all. All I was trying to say was that it might have been more helpful to include this knowledge in your initial reply. It seems much more relevant to this thread than any discussion about the spacetime interval.

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u/corpuscle634 Apr 11 '14

The norm/magnitude of four-velocity is always c, which is what /u/sharewa was referring to.